문제
https://www.acmicpc.net/problem/1189
풀이
dfs탐색으로 모든 경우의 수를 탐색해준다
Java Code
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class boj1189 {
static int R, C, K;
static char[][] map;
static int[][] visited;
static int answer;
static int[] moveR = {1, -1, 0, 0};
static int[] moveC = {0, 0, 1, -1};
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer(br.readLine());
R = Integer.parseInt(st.nextToken());
C = Integer.parseInt(st.nextToken());
K = Integer.parseInt(st.nextToken());
map = new char[R][C];
visited = new int[R][C];
for (int i = 0; i < R; i++) {
String s = br.readLine();
for (int j = 0; j < C; j++) {
map[i][j] = s.charAt(j);
}
}
visited[R - 1][0] = 1;
dfs(R - 1, 0, 1);
System.out.println(answer);
}
static void dfs(int r, int c, int moved) {
if (r == 0 && c == C - 1) {
if (moved == K) {
answer++;
}
return;
}
for (int i = 0; i < 4; i++) {
int nextR = r + moveR[i];
int nextC = c + moveC[i];
if (nextR < 0 || nextR >= R || nextC < 0 || nextC >= C) {
continue;
}
if (visited[nextR][nextC] == 1 || map[nextR][nextC] == 'T') {
continue;
}
visited[nextR][nextC] = 1;
dfs(nextR, nextC, moved + 1);
visited[nextR][nextC] = 0;
}
}
}
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