문제

https://www.acmicpc.net/problem/1189

풀이

dfs탐색으로 모든 경우의 수를 탐색해준다

Java Code

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class boj1189 {

    static int R, C, K;
    static char[][] map;
    static int[][] visited;
    static int answer;

    static int[] moveR = {1, -1, 0, 0};
    static int[] moveC = {0, 0, 1, -1};

    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer(br.readLine());
        R = Integer.parseInt(st.nextToken());
        C = Integer.parseInt(st.nextToken());
        K = Integer.parseInt(st.nextToken());
        map = new char[R][C];
        visited = new int[R][C];

        for (int i = 0; i < R; i++) {
            String s = br.readLine();
            for (int j = 0; j < C; j++) {
                map[i][j] = s.charAt(j);
            }
        }

        visited[R - 1][0] = 1;
        dfs(R - 1, 0, 1);

        System.out.println(answer);

    }

    static void dfs(int r, int c, int moved) {
        if (r == 0 && c == C - 1) {
            if (moved == K) {
                answer++;
            }
            return;
        }

        for (int i = 0; i < 4; i++) {
            int nextR = r + moveR[i];
            int nextC = c + moveC[i];
            if (nextR < 0 || nextR >= R || nextC < 0 || nextC >= C) {
                continue;
            }
            if (visited[nextR][nextC] == 1 || map[nextR][nextC] == 'T') {
                continue;
            }
            visited[nextR][nextC] = 1;
            dfs(nextR, nextC, moved + 1);
            visited[nextR][nextC] = 0;

        }

    }

}

 

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